I am trying to make the program print out "OK" for as long as i enter 'y' as a choice at the end, but it is not looping, it just prints out "OK" and ends the program even if i enter a 'y' at the end. Please help.
#include <stdio.h> int main() { char c = 'y'; while (c == 'y') { printf_s("OK\n"); scanf_s("%c", &c); if (c != 'y') { break; } } return 0; } On first iteration when you press Enter key then a newline character \n is passed to the input along with y. On second iteration scanf_s reads \n. Change
scanf_s("%c", &c); to
scanf_s(" %c", &c); ^Notice the space before %c A space before %c specifier can consume any number of white-space characters.
scanf_s method requires that all storage locations be followed with an explicit size.Change the scanf_s line as follows
scanf_s("%c", &c, 1); This extra parameter is specifying the size of the c argument. Plain old scanf doesn't require this argument but the versions ending with _s do
Also the if block with the break statement is unnecessary because the conditional on the while loop effectively does the same thing. It could be written as follows
while (c == 'y') { printf_s("OK\n"); scanf_s("%c", &c, 1); } OK I used scanf instead of scanf_s, that solved the problem, thanks everyone.
scanf_s see my answer as it corrects the usage of htis APIYou are wrong with scanf
if you use like this u will see it is working ..
#include <stdio.h> int main() { int c = 1; while (c == 1) { printf_s("OK\n"); scanf_s("%d", &c); if (c != 1) { printf_s("hello\n"); continue; } } return 0; } 
Put a space before %c to skip whitespace.
fflush(stdin)before scanfscanf_sreference.