Java Take String input from console

Question

I was trying to take string input in java. My input should be like this

3 1,1,[email protected],123 Sesame St.,New York,NY,10011,12345689010 1,2,[email protected],123 Sesame St.,New York,NY,10011,12345689010 1,3,[email protected],123 Sesame St.,New York,NY,10011,12345689010

So, I tried this

Scanner in = new Scanner(System.in); int TotalNumber = in.nextInt(); String[] Data = new String[TotalNumber]; for (int Counter = 0; Counter < TotalNumber; Counter++) { Data[Counter] = in.next(); } in.close(); for (int counter = 0; counter < Data.length; counter++) { System.out.println(Data[counter]); }

My output is showing this

1,1,[email protected],123 Sesame St.,New

What is my problem ? How take input string line properly ?

Update

I found my solution at here Scanner issue when using nextLine after nextXXX

Mureinik · Accepted Answer · 2014-02-09 16:46:34Z

1

next() breaks at a whitespace. Instead, you should use nextLine() to input the entire line to your string:

int TotalNumber = in.nextInt(); String[] Data = new String[TotalNumber]; for (int Counter = 0; Counter < TotalNumber; Counter++) { Data[Counter] = in.nextLine(); }

answered Feb 9, 2014 at 16:46

Mureinik

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4 Comments

Kona Ahmed Over a year ago

I tried with nextLine() 3 1,1,[email protected],123 Sesame St.,New York,NY,10011,12345689010 1,1,[email protected],123 Sesame St.,New York,NY,10011,12345689010 it only take 2 inputs from me

JavaTechnical Over a year ago

could you explain what happened? I mean the output.

Kona Ahmed Over a year ago

First I gave 3(It should take 3 lines of string right ?) then hit entered first line then again hit enter and the second line then I hit enter and only two lines are showing. But, It should be take 3 lines and show 3 lines

JavaTechnical Over a year ago

I think an enter was pressed accidentally? Are you seeing the same output always.

Rakesh KR · Accepted Answer · 2014-02-09 16:47:33Z

0

Try with Data[Counter] = in.nextLine();

answered Feb 9, 2014 at 16:47

Rakesh KR

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Comments

Lefteris Bab · Accepted Answer · 2014-02-09 17:00:52Z

What about:

import java.util.Scanner; import java.lang.String; public class Test { public static void main(String[] args) { char[] sArray; Scanner scan = new Scanner(System.in); System.out.print("Enter a Palindrome : "); String s = scan.nextLine(); s = s.replaceAll("\\s+", ""); sArray = new char[s.length()]; for(int i = 0; i < s.length(); i++) { sArray[i] = s.charAt(i); System.out.print(sArray[i]); } } }

JavaTechnical · Accepted Answer · 2014-02-09 17:09:19Z

Try this (Mureinik modified code)..

int TotalNumber = in.nextInt(); in.nextLine(); String[] Data = new String[TotalNumber]; for (int Counter = 0; Counter < TotalNumber; Counter++) { Data[Counter] = in.nextLine(); }

You need a nextLine() after taking the int because you will press enter after taking int and that enter is read by nextLine() in the Data[0].

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