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Is it possible to get the class calling a function in JavaScript?

For example:

function Foo(){ this.alertCaller = alertCaller; } function Bar(){ this.alertCaller = alertCaller; } function alertCaller(){ alert(*calling object*); }

When calling the Foo().alertCaller() i want to output the class Foo() and when calling Bar().alertCaller() I want to outbut Bar(). Is there any way I can do this?

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  • caller... but its invalid in strict mode. Commented Feb 12, 2014 at 15:19
  • Yeah, I know about that is there no workaround? Commented Feb 12, 2014 at 15:20
  • @kei No, I'm trying to do a different thing here. Commented Feb 12, 2014 at 15:20
  • Since when does JavaScript have classes? ;) Commented Feb 12, 2014 at 15:22

3 Answers 3

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4

Try this :

function alertCaller(){ alert(this.constructor); }
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That will show the current objects class not the caller's
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You really should use strict mode

What is strict mode ?

I recommend you not to do what you want to do.

There is probably a better design answering to your needs.

If you still want to get the caller

This is what you'd use if you haven't strict mode enabled

function alertCaller(){ alert(arguments.callee.caller); }
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1

if i understand you ..

function Foo(){ this.alertCaller = alertCaller; } function Bar(){ this.alertCaller = alertCaller; } Foo.prototype.alertCaller = function() { alert('Foo'); } Bar.prototype.alertCaller = function() { alert('Bar'); } foo = new Foo(); foo.alertCaller(); Bar= new Foo(); Bar.alertCaller();
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This is also a good method for passing variables to certain functions only! Thank you!

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