First i got a doubt that, when I create a string as
String s = new String("Stack"); whether "Stack" is saved in String Constant pool or not?
but this post : what happens with new String("") in String Constant pool tell that it is not.
but according to answers of this post : where do actual parameters in java store tell that it is present in Constant pool.
Please give a clarification on this.
If you do:
String s = "Stack"; .. then the literal string "Stack" is, in fact, a part of the constant string pool. When you do:
String s = new String("Stack"); ... however, the original literal string "Stack" is a part of the string pool, but the use of "new" here forces a copy to be constructed that is not in the constant pool.
String s=new String("Stack"); For the above statement, there will be a String literal Stack created in the constant pool, and in the heap, there will be another String object which will be referred by reference s.
When you do something like this:
String a = "ang"; String b = "ang"; Both String a and b point to same "ang". Reference would be same because they both point to "ang" in string pool.
But when you do:
String a = new String("ang"); String b = new String("ang"); They both point to different objects.
but this post : what happens with new String("") in String Constant pool tell that it is not.
No it doesn't. See the first comment: 'Both. Both. Both.' Or the accepted answer: "'intern()' or string literal".
but according to answers of this post : where do actual parameters in java store tell that it is present in Constant pool.
Correct. The compiler puts the string literals there, and intern() puts dynamic strings there.
