shell script on node.js

Question

I am very new to node.js, I am trying to create a node.js script with the execution of shell script in it.

Here is the code which i have .

var spawn = require('child_process').spawn var _ = require('underscore'); var deploySh = spawn('sh', [ 'vij.sh' ], { cwd: process.env.HOME + '/u/qa/gv/node/scripts', env:_.extend(process.env, { PATH: process.env.PATH + ':/usr/local/bin' }) });

and when i try to execute it, i am facing the below issue. Can anyone help me on this?

node vijay events.js:72 throw er; // Unhandled 'error' event ^ Error: spawn ENOENT at errnoException (child_process.js:988:11) at Process.ChildProcess._handle.onexit (child_process.js:779:34)

You can drop sh and use spawn('vij.sh') - make sure that vij.sh has #!/bin/sh as the first line. — Jay
– Jay, Commented Feb 20, 2014 at 21:08
Hi, I have the #!/bin/sh at the first line. I modified the spawn but i get the same issue. — user3334590
– user3334590, Commented Feb 20, 2014 at 21:22
Hi Henk, yes i tried /bin/sh instead of sh, its the same error. — user3334590
– user3334590, Commented Feb 20, 2014 at 21:24

smertrios · Accepted Answer · 2014-02-21 00:49:13Z

spawn is complaining that it can't find 'sh', use 'bash' instead (you might also need to specify the full path to your script depending on your env setup.)

so I'd try:

spawn('bash', ['vij.sh'], ...
spawn('bash', ['/my/path/to/vij.sh'], ...
spawn('/my/path/to/vij.sh', [], ...

nhahtdh · Accepted Answer · 2015-03-19 02:46:51Z

var spawn = require('child_process').spawn var _ = require('underscore'); var deploySh = spawn('sh', [ 'vij.sh' ], { // cwd: process.env.HOME + '/u/qa/gv/node/scripts', env:_.extend(process.env, { PATH: process.env.PATH + ':/usr/local/bin' }) });

Comment cwd: line no. 4

Until now I don't know what is process.env.HOME value but this worked for me.

Collectives™ on Stack Overflow

shell script on node.js

2 Answers 2

Comments

Comments

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Related