Constructor similar to std::map or std::vector in a class

Question

I'm creating a class and I want to know how to create a constructor similar to the std::map or std::vector style.

std::map<std::string, std::string> map = { {"foo", "bar"}, {"biz", "buz"}, {"bez", "boz"} };

The difference is that I don't want my class to ask for types that wants to accept, just like std::map does.

std::map<std::string, std::string>

I want my class to accept that style of arguments:

{ {"foo", "bar"}, {"biz", "buz"}, {"bez", "boz"} };

But with defined type. (std::string, Typer)

The 'Typer' is a class that I will insert as value on the std::map.

The simple answer is: use the map as the second parameter, as follows: const std::map<std::string, std::string>& data. In this case you can use your syntax for the second parameter. This is not a duplicate question, by the way. You needn't use an initializer list here. This works both in VS2013 and GCC 4.8.1. — Mikhail Semenov
– Mikhail Semenov, Commented Mar 2, 2014 at 10:54

fredoverflow · Accepted Answer · 2014-02-28 16:37:32Z

If I understand your question correctly, you want a constructor taking std::initializer_list<std::pair<std::string, Typer>>, like this:

struct Typer { std::string data; Typer(const char *s) : data(s) {} }; struct MyClass { MyClass(std::initializer_list<std::pair<std::string, Typer>> i) : myMap(begin(i), end(i)) {} std::map<std::string, Typer> myMap; }; int main() { MyClass m = { {"foo", "bar"}, {"biz", "buz"}, {"bez", "boz"} }; }

Live example

Lightness Races in Orbit · Accepted Answer · 2014-02-21 15:53:00Z

3

typedef std::map<std::string, Typer> MyType;

answered Feb 21, 2014 at 15:53

Lightness Races in Orbit

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