Get the function name from it's body in Ruby [duplicate]

Question

Say I have a function:

def foo() puts getFunctionIAMIn() end

I want the output to be:"foo" And if I have this code:

def foo1() puts getFunctionIAMIn() end

I want the output to be:"foo1"

The question, in a different phrasing, how do I realize getFunctionIAMIn() ? — user1134991
– user1134991, Commented Mar 6, 2014 at 13:26

Arup Rakshit · Accepted Answer · 2014-03-06 13:59:14Z

5

Just write as below using __method__:

def foo() puts __method__ end

Above is correct, but __callee__ sounds more technically correct.

__method__ returns defined name, and __callee__ returns called name.They are same usually, but different in a aliased method.

def foo [__method__, __callee__] end alias bar foo p foo #=> [:foo, :foo] p bar #=> [:foo, :bar]

answered Mar 6, 2014 at 13:28

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7 Comments

You beat me by 8 seconds :D

Do you know how it is different from __callee__?

@Stefan No they are not... :)

@sawa Got your point.. __callee__ is more technically correct.. Let me edit.

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Severin · Accepted Answer · 2014-03-06 13:29:13Z

2

You can use __method__ for that:

def test_method __method__ end

answered Mar 6, 2014 at 13:29

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Do you thin your answer and my one is different ?