This is ugly. What's a more Pythonic way to do it?
import datetime t= (2010, 10, 2, 11, 4, 0, 2, 41, 0) dt = datetime.datetime(t[0], t[1], t[2], t[3], t[4], t[5], t[6]) 
- 6You may want to read about it in the docs: docs.python.org/tutorial/…Nadia Alramli– Nadia Alramli2010-02-10 16:18:38 +00:00Commented Feb 10, 2010 at 16:18
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2 Answers
Generally, you can use the func(*tuple) syntax. You can even pass a part of the tuple, which seems like what you're trying to do here:
t = (2010, 10, 2, 11, 4, 0, 2, 41, 0) dt = datetime.datetime(*t[0:7]) This is called unpacking a tuple, and can be used for other iterables (such as lists) too. Here's another example (from the Python tutorial):
>>> range(3, 6) # normal call with separate arguments [3, 4, 5] >>> args = [3, 6] >>> range(*args) # call with arguments unpacked from a list [3, 4, 5] 
5 Comments
Mike Graham
It works for arbitrary iterables.
Nearoo
I'd like to add that this syntax works anywhere (not just in function calls) in python 3.5, so for instance statements like
x, y, z = *(1, 2, 3) will work without error (as it should have been a long time ago)
Dannid
it there a way to do this among other list items? like
my_tuple = ("B", "C"); "%s %s %s" % ("A", *my_tuple)?Dannid
Nevermind - I think this is a limitation of the %s string substitution method. Using
"{} {} {}".format("A", *my_tuple) instead does the trick.
dopatraman
Does anyone know any details about how Python implements unpacking internally?
Refer https://docs.python.org/2/tutorial/controlflow.html#unpacking-argument-lists
dt = datetime.datetime(*t[:7]) 
