Why is the PHP assignment operator acting as an assignment by reference in this case?

Question

I have some code that appears to behave differently between PHP 4 and PHP 5. This code below:

class CFoo { var $arr; function CFoo() { $this->arr = array(); } function AddToArray($i) { $this->arr[] = $i; } function DoStuffOnFoo() { for ($i = 0; $i < 10; ++$i) { $foo2 = new CFoo(); $foo2 = $this; // I expect this to copy, therefore // resetting back to the original $this $foo2->AddToArray($i); echo "Foo2:\n"; print_r($foo2); echo "This:\n"; print_r($this); } } } $foo1 = new CFoo(); $foo1->DoStuffOnFoo();

Previously, in PHP 4, the assignment of $foo2 above would reset $foo2 back to the value that $this was originally set at. In this case, I would expect it to be set to a CFoo with an empty $arr member. However, the assignment of $foo2 to $this is acting as an assignment by reference. Foo2 is acting as an alias to this. Therefore when I call "AddToArray" on foo2, $this's $arr is also being appended to. So when I go to reassign foo2 back to this, instead of getting the initial value of this, I get essentially a self assignment.

Has this behavior changed in PHP 5? What can I do to force foo2 to make a copy of this?

Peter Mortensen · Accepted Answer · 2015-12-05 23:47:07Z

The object-oriented part of PHP has been hugely overhauled in PHP 5. Objects are now passed (not exactly but almost) as references. See http://docs.php.net/clone.

Example:

$x1 = new StdClass; $x1->a = 'x1a'; $x2 = $x1; $y = clone $x1; // Performing operations on x2 affects x1 / same underlying object $x2->a = 'x2A'; $x2->b = 'x2B'; // y is a clone / changes do not affect x1 $y->b = 'yB'; echo 'x1: '; print_r($x1); echo 'y:'; print_r($y);

prints

x1: stdClass Object ( [a] => x2A [b] => x2B ) y:stdClass Object ( [a] => x1a [b] => yB )

Peter Mortensen · Accepted Answer · 2015-12-05 23:48:59Z

In PHP 4 a copy was made of an object iunless you assigned it by reference (using &=). In PHP 5 a reference to the object is assigned.

So after assigning $this to $foo2, $foo2 points to $this and not to a new copy of CFoo.

To make a copy in PHP 5 you say clone $this.

In either case, the previous new statement is wasted.

Peter Mortensen · Accepted Answer · 2015-12-05 23:50:13Z

2

Yes, PHP 5 is now copying by reference. Now you have to clone the object to make a copy of it.

edited Dec 5, 2015 at 23:50

Peter Mortensen

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answered Feb 12, 2010 at 14:23

t00ny

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Peter Mortensen · Accepted Answer · 2015-12-05 23:49:45Z

1

PHP has used references since version 5. To copy objects, use:

$copy = clone $object;

edited Dec 5, 2015 at 23:49

Peter Mortensen

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answered Feb 12, 2010 at 14:20

Martin Wickman

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