How to store argparse values in variables?

Question

I am trying to add command line options to my script, using the following code:

import argparse parser = argparse.ArgumentParser('My program') parser.add_argument('-x', '--one') parser.add_argument('-y', '--two') parser.add_argument('-z', '--three') args = vars(parser.parse_args()) foo = args['one'] bar = args['two'] cheese = args['three']

Is this the correct way to do this?

Also, how do I run it from the IDLE shell? I use the command 'python myprogram.py -x foo -y bar -z cheese' and it gives me a syntax error

khagler · Accepted Answer · 2014-03-21 22:42:12Z

That will work, but you can simplify it a bit like this:

args = parser.parse_args() foo = args.one bar = args.two cheese = args.three

Greg · Accepted Answer · 2014-03-21 22:14:59Z

7

use args.__dict__

args.__dict__["one"] args.__dict__["two"] args.__dict__["three"]

answered Mar 21, 2014 at 22:14

Greg

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4 Comments

David Pointer Over a year ago

I agree your solution is correct. And interesting,. At the same time, some people on SO get really cranky and downvote if a Python domain answer is not in what they see as acceptable pythonic form. Meh. Even though what is "acceptable" changes over time.

Greg Over a year ago

@DavidPointer is what it is I guess. Thanks for the pity votes :P

Giacomo Pigani Over a year ago

I don't know. After all the OP already used vars() which already returns the _dict_

gvo Over a year ago

It's "working" but it's to be avoided. The presence of the underscores is a strong hint that these methods are not intended to be invoked directly. Therefore, yes, it's working, but no, it's not a good answer. So I understand that some people downvote it.

sophros · Accepted Answer · 2020-02-12 13:38:06Z

The canonical way to get the values of the arguments that is suggested in the documentation is to use vars as you did and access the argument values by name:

argv = vars(args) one = argv['one'] two = args['two'] three = argv['three']

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