How can i do crop multiple image in a batch

I would suggest you use ImageMagick, which is available for free for Windows, Linux and OSX from here

For example, to crop all jpegs in current directory to 256 pixels max by 256 pixels max

mogrify -resize 256x256 *.jpg 

For your purposes, assuming an input file is called a.jpg, you probably need

convert a.jpg -crop 465x800+465+0 +repage a2.jpg convert a.jpg -crop 465x800+0+0 +repage a1.jpg 

and a1.jpg and a2.jpg will be the two halves,

I don't know if you are on Windows or Linux, but you can put this in a loop easily enough to do all your images

Untested:

Linux...

for f in *.jpg do newbase=$(basename "$f") convert "$f" -crop 465x800+465+0 +repage "${newbase}_1.jpg" convert "$f" -crop 465x800+0+0 +repage "${newbase}_2.jpg" done 

MS-DOS Command (my skills are rusty here)

FOR %a in (*.jpg) DO something 

Back up your images before you try any commands!!!

Assuming you have a folder with images (recursive), just images, no other files... Assuming all these images are large enough to split... you can use this script

I'm using this to split 3840x1080 images into 2 1920x1080 images for dual screen desktop background images.

#!/bin/bash files=$(find -type f) basedir=$(pwd) width=1920 height=1080 for f in $files do dir=$(dirname "$f") cd $dir file=$(basename "$f") newfile=$(echo $file | cut -d. -f1) convert "$file" -crop ${width}x${height}+0+0 +repage "${newfile}_1_of_2.jpg" convert "$file" -crop ${width}x${height}+${width}+0 +repage "${newfile}_2_of_2.jpg" cd $basedir done 

You can try crop.bat (does not require external binaries):

call crop.bat -source image.jpg -target image-left.jpg -percentage yes -right 50 -force yes call crop.bat -source image.jpg -target image-right.jpg -percentage yes -left 50 -force yes 

For mass image cropping you can check the for command.