Django ImageField overwrites existing path when empty

Question

So, that's the problem: I currently have a model:

 class UserData(models.Model): avatar = models.ImageField(verbose_name='Avatar',upload_to='images/profile_pics',blank=True,null=True) doc_type = models.CharField(verbose_name='Document type',max_length=1,default='0')

And a form:

 class UserCreationForm(forms.ModelForm): avatar = forms.ImageField(label='Avatar',required=False, error_messages = {'invalid':"Images only"}, widget=forms.FileInput) class Meta: model = UserData

So, the problem occurs when the user tries to edit his data. When no image is provided, the current image path in the db overwrites with the empty string. Is there any way to solve that problem?

So, I have to check if the image is provided, and then decide whether to save it or not? — Creon12
– Creon12, Commented Apr 8, 2014 at 11:53
exactly, if there is an empty value send by your form, just ignore it, else set the send value... — Jingo
– Jingo, Commented Apr 8, 2014 at 12:31

Tolqinbek Isoqov · Accepted Answer · 2018-09-16 19:17:37Z

avatar = models.ImageField(verbose_name='Avatar',upload_to='images/profile_pics',null=True)

removing blank=True should solve it

Al Amin · Accepted Answer · 2019-10-08 10:59:34Z

You can solve the problem by making image field required.

avatar = forms.ImageField(label='Avatar', required=True, error_messages={'invalid':"Images only"}, widget=forms.FileInput)

Alireza Bahrami · Accepted Answer · 2020-10-10 19:55:10Z

Remove both blank and null equal to True

blank=True

Allows the field to be empty

null=True

Allows the empty data to be saved in database

so you can choose which one will work for you the best.

Mykhailo Lyvak · Accepted Answer · 2023-12-14 11:13:56Z

from django.db import connection @login_required

def card_photo_remove(request, pk): card = get_object_or_404(Cards, cardid=pk)

if card.sponsorimage: default_storage.delete(card.sponsorimage.path) with connection.cursor() as cursor: cursor.execute("UPDATE Cards SET SponsorImage=NULL WHERE cardid=%s", [pk]) return HttpResponseRedirect(request.META.get('HTTP_REFERER'))

Here u can see exaple how to write manyal SQL code. It worked to me perfectly!

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