Is this possible in Python? I wrote a great loop/script in Python and I’d like to add this delay to it if at all possible.
map(firefox.open, ['http://www.bing.com/search?q=' + str(i) for i in range(x))], [2] * x) Where shall I put the sleep(6) in this?
You can do that using time.sleep(some_seconds).
from time import sleep for i in range(10): print i sleep(0.5) #in seconds Here is a cool little implementation of that: (Paste it in a .py file and run it)
from time import sleep for i in range(101): print '\r'+str(i)+'% completed', time.sleep(0.1) map(firefox.open, ['http://www.bing.com/search?q=' + str(i) for i in range(x))], [2] * x)
map(firefox.open, ['http://www.bing.com/search?q=' + str(i) for i in range(x))], [2] * x) Where shall I put the sleep(6) in this?
firefox.open and stuff so I am currently not understanding.Or if you want it to start on one and emulate a stopwatch:
import time def count_to(number): for i in range(number): time.sleep(1) i += 1 if i >= number: print('Time is up') break print(i) Yes it is possible in python you should use 'time' module:
>>> import time >>> list1=[1,2,3,4,5,6,7,8,9,10] >>> for i in list1: time.sleep(1)#sleep for 1 second print i output :
1 2 3 4 5 6 7 8 9 10 