Uploading a file using RESTful API based on Grails JAX-RS Plugin

Question

I'm trying to get a file with a RESTful API based with JAX-RS on Grails.The file is sent from a regular POST multi-part form with file input tag. ( For sending the file I'm using postman google extention )

But after sending the request I get "HTTP Status 400 - Bad Request" response. I checked many tutorials and followed exactly their steps but it's not working.

Here is the the code in REST service to handle the request :

import com.sun.jersey.multipart.FormDataParam import com.sun.jersey.core.header.FormDataContentDisposition; import org.json.simple.JSONObject import javax.servlet.http.HttpServletRequest import javax.servlet.http.HttpServletResponse import javax.ws.rs.Consumes import javax.ws.rs.FormParam import javax.ws.rs.GET import javax.ws.rs.POST import javax.ws.rs.Path import javax.ws.rs.PathParam import javax.ws.rs.Produces import javax.ws.rs.QueryParam import javax.ws.rs.core.Context import javax.ws.rs.core.Response; import javax.ws.rs.core.MediaType import javax.ws.rs.core.MultivaluedMap import java.io.File; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.io.OutputStream; @Path('/api/upload/') class UploadResource { @POST @Path("/tst") @Consumes(MediaType.MULTIPART_FORM_DATA) @Produces('application/json') public String uploadFile(@FormDataParam("file") InputStream is, @FormDataParam("file") FormDataContentDisposition fileDetail){ String uploadedFileLocation = "Some Location"; // save it saveToFile(is, uploadedFileLocation); JSONObject JObject = new JSONObject(); JObject.put("Message", "Aha") JObject.put("Response", "200") JObject.put("Status", "OK") return JObject.toJSONString() } }

And here is the way I send the file :

http://postimg.org/image/x3wfrs6h5/

Denny · Accepted Answer · 2014-05-05 15:44:40Z

Instead of disabling Grails' multipart resolver completely for the whole application (see: https://code.google.com/p/grails-jaxrs/issues/detail?id=52#c11) you could get the file by accessing the multipart file from Grails' WebUtils Holder.

@POST @Path("/tst") @Consumes(MediaType.MULTIPART_FORM_DATA) @Produces('application/json') public String uploadFile() { String uploadedFileLocation = "Some Location"; // here is the workaround for issue: https://code.google.com/p/grails-jaxrs/issues/detail?id=52 GrailsWebRequest request = WebUtils.retrieveGrailsWebRequest() MultipartFile multipartFile = request.getRequest().getFile('file') def is = multipartFile.inputStream // save it saveToFile(is, uploadedFileLocation); JSONObject JObject = new JSONObject(); JObject.put("Message", "Aha") JObject.put("Response", "200") JObject.put("Status", "OK") return JObject.toJSONString() }

Denny · Accepted Answer · 2014-04-28 15:34:07Z

The problem occures because the controller initiated by the jaxrs plugin parses the request upfront and this leads to the error.

This problem is known and there is a workaround for this: https://code.google.com/p/grails-jaxrs/issues/detail?id=52#c11 But it is still a known bug on jaxrs plugin.

AVS · Accepted Answer · 2017-01-23 01:16:22Z

By default Grails defines a bean named 'multipartResolver' defined for CommonsMultipartResolver, but this does not work with jax-rs as per the reasons detailed by Denny.

The only issue I see with his proposal to use GrailsWebRequest is that if you go to YOUR_APP_URL/application.wadl, you will not see the file param there and therefore auto-generated client code will not work.

What I have done is override this in resources.groovy to:

multipartResolver(org.springframework.web.multipart.support.StandardServletMultipartResolver) { bean -> bean.autowire = 'byName' }

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