I am currently trying to replace a single character in a string with more than one number. Lets make it quick:
replace(string.begin(), string.end(), 'a', '1'); ^ WORKS! ^
replace(string.begin(), string.end(), 'a', '11'); or
replace(string.begin(), string.end(), 'a', "1"); ^ DOESN'T WORK! ^
How do I do it? Is there any function for it?
NOTE: I'm not asking how to:
You should use some overloaded member function replace of class std::basic_string instead of the standard algorithm std::replace.
For example
for ( std::string::size_type pos = 0; ( pos = s.find( 'a', pos ) ) != std::string::npos; pos += 2 ) { s.replace( pos, 1, 2, '1' ); } Or if the number can be any arbitrary string then you can write
std::string number( "123" ); for ( std::string::size_type pos = 0; ( pos = s.find( 'a', pos ) ) != std::string::npos; pos += number.size() ) { s.replace( pos, 1, number ); } If you want to replace a number with a character then you can write
for ( std::string::size_type pos = 0; ( pos = s.find( "11", pos ) ) != std::string::npos; ++pos ) { s.replace( pos, 2, 1, 'a' ); } 
You need to give the same type of argument as the value to be replaced and the replacing value.
'a' is a char, while "1" is a string. You can't mix those two, replace in this case only supports chars.
Note: '11' is not a valid char.
'11' might be valid for certain implementations. See this question for example.
int and not of type char.
'11'is a multi-character-literal, having typeint. It is most likely not remotely what you think it is.