Delete Line before and after found pattern

Question

I have a configuration that is disabled because its embedded in a comment. My Sed is deleting the line beneath my pattern, but the line with the pattern gets deleted too. Can I tell Sed to keep the current line? Or just delete the line before and after the found pattern.

Input

... <!-- <Connector port="8009" protocol="AJP/1.3" redirectPort="8443" /> --> ...

Sed

# sed -e '/<Connector port="8009" protocol="AJP\/1.3" redirectPort="8443" \/>/,+2d' server.xml

Output

... <!-- ...

Wish to be Output:

... <Connector port="8009" protocol="AJP/1.3" redirectPort="8443" /> ...

Your config seems to be an XML document. Use a proper XML parser to process it. — choroba
– choroba, Commented Jun 5, 2014 at 13:09

choroba · Accepted Answer · 2014-06-05 13:18:32Z

3

Your input seems to be an XML document. Use a proper parser to process it. For example, xsh:

open server.xml ; for my $c in //comment()[contains(.,'<Connector port="8009" protocol="AJP/1.3" redirectPort="8443" />')] xinsert chunk $c replace $c ; save :b ;

answered Jun 5, 2014 at 13:18

choroba

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3 Comments

Dan Fego Over a year ago

I have no idea if your snippet is correct, but this is the correct approach. +1

choroba Over a year ago

@DanFego: Thanks. I tested it on a server.xml I created myself, as no sample input file was given. :-)

jaypal singh Over a year ago

Using the right tool for the right job is hardly one ever wants. :P.

potong · Accepted Answer · 2014-06-05 13:16:55Z

This might work for you (GNU sed):

sed '$!N;/\n<Connector port="8009" protocol="AJP\/1.3" redirectPort="8443" \/>/{s/.*\n//p;$!N;d};P;D' file

Keep 2 lines in the pattern space and delete the first, print the next and delete the following line if the pattern is found.

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