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I need get the current log in user in Jenkins, I am using a Groovy parameter but I don't know how to get that,

Thanks,

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    Isn't it User.current()? Commented Jun 11, 2014 at 15:36
  • Yes is it, thanks man I have several days searching that Commented Jun 11, 2014 at 15:41
  • Added as an answer :-) Have fun! Commented Jun 11, 2014 at 15:48
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    returns SYSTEM ! Commented Jun 18, 2018 at 14:33

3 Answers 3

Reset to default
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You should be able to call:

import hudson.model.User ... User.current()

From a groovy script to get the current user :-)

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In script pipeline, it returns SYSTEM
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def user = build.causes[0].userId

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Since build by itself doesn't exist it should be currentBuild.rawBuild.causes[0].userId, but thanks for pointing me in the right direction, User.current() does indeed return 'SYSTEM'. Have some points.
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import hudson.model.* def job = Jenkins.getInstance().getItemByFullName(env.JOB_BASE_NAME, Job.class) def build = job.getBuildByNumber(env.BUILD_ID as int) def userId = build.getCause(Cause.UserIdCause).getUserId() def user = User.current() println(user); println(userId); ----- this is the output [Pipeline] echo (hide) SYSTEM [Pipeline] echo eefrat [Pipeline] echo eefrat
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Welcome to Stack Overflow. Please add a few words to help explain your answer.
I'm not sure I understood... userId gives you the user who triggered the build or the user who's logged in?

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