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I am trying to retrieve image using the image path (which saved in the database) in the array index.

like-

< img src= "< ? php echo base_url().$info['/assets/img/women_collection/2/main_image_gallery.jpg'];? >" / > 

But it does not woring!.

plz help! .

2
  • What errors are you getting? Commented Jun 25, 2014 at 16:33
  • 1
    Please, pass your path as a parameter to base_url() Commented Jun 25, 2014 at 16:40

1 Answer 1

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I assume $info is your database results?

Your array key should be the database table row.

$info['image'] 
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2 Comments

it's real foolishness !!! :P i was using the image path instead of using the database row!! the index should be the row of the database. like this- < img src= " < ? php echo base_url().$info['gallery_image']; ? > " / >
You're welcome. You should follow Brett's advice too, and pass this as a parameter to the base_url function.

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