I need to do bitwise OR of two binary strings.
For example, if the binary strings are '110001' and '101101', then I need the result as '111101'.
I tried this, but it gave me strange results.
console.log(110001 | 101101); 
2 Answers
You can't write binary numbers as literals in JavaScript. The only numeric literals allowed are:
- Decimal:
1337(One thousand and thirty-seven). - Octal:
02471(One thousand and thirty-seven in base 8). - Hexadecimal:
0x539(One thousand and thirty-seven in base 16).
To write binary numbers you need to use parseInt with base 2. To convert a number to binary representation you use toString with base 2. Hence you would write it as:
var a = parseInt("110001", 2); var b = parseInt("101101", 2); var c = a | b; console.log(c.toString(2)); Simple.
Comments
You need to explicitly cast the binary representation to it's int equivalent. (otherwise it's interpreted as 110001 (base 10)):
console.log((parseInt('110001',2) | parseInt('101101',2)).toString(2)); The output is then cast back to it's base 2 representation (string)
console.log((parseInt("110001", 2) | parseInt("101101", 2)).toString(2))?