Create instance of type with params argument in PowerShell

Question

I am trying to create an instance of given type in PowerShell using New-Object. The constructor of the type being instantiated is having an argument of type [string params]. For example,

public class Test { public Test(params string[] data) { // } }

If I try to instantiate the above type using following command:

$ins = New-Object Test

I am getting the following error:

System.Management.Automation.PSArgumentException: Constructor not found. Cannot find an appropriate constructor for type.....

What is the correct way of instantiating the above type? I don't want to pass any dummy or empty string as input parameter.

The above sample code was only for demonstration purposes. The class that I am trying to instantiate is StandardKernel from Ninject library. The class definition is given below:

public class StandardKernel : KernelBase { public StandardKernel(params INinjectModule[] modules) : base(modules) { } public StandardKernel(INinjectSettings settings, params INinjectModule[] modules) : base(settings, modules) { } }

The following code works fine in C#:

var kernel = new StandardKernel()

Your code still doesn't have a default constructor. Try adding a line public StandardKernel() : base() {}. — Ansgar Wiechers
– Ansgar Wiechers, Commented Jul 16, 2014 at 10:27

Rynant · Accepted Answer · 2014-07-15 15:32:23Z

After understanding your issue better, I don't know of a way to create the object with pure PowerShell, but you could create a C# method that will return what you want (see the NewTest type below).

$code1 = @' public class Test { public string arguments; public Test(params string[] data) { if(data != null) arguments = string.Join(", ", data); } } '@ $null = Add-Type -TypeDefinition $code1 -OutputAssembly c:\temp\Test.dll -PassThru $code2 = @' public class NewTest { public static Test GetTest() { return new Test(); } } '@ Add-Type -TypeDefinition $code2 -ReferencedAssemblies c:\temp\Test.dll [NewTest]::GetTest()

Ansgar Wiechers · Accepted Answer · 2014-07-15 14:37:42Z

Aside from the issue with the params keyword that @Rynant had pointed out, your class constructor expects a parameter, but you don't provide one when trying to instantiate an object.

You could instantiate the object with an empty string to deal with this:

$src = @" public class Test { public Test(params string[] data) { //... } } "@ Add-Type -TypeDefinition $src $ins = New-Object Test ''

or you could overload the constructor:

$src = @" public class Test { public Test(params string[] data) { //... } public Test() : this("") {} } "@ Add-Type -TypeDefinition $src $ins = New-Object Test

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