Input
aaaa bbbb cccc Output
aaaa < _jupijuice_ > bbbb < _jupijuice_ > cccc < _jupijuice_ > In simple words, replace \n with \n< jupijuice >\n
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4 Answers
awk '{print; print "< _jupijuice_ >"}' input.txt Output:
aaaa < _jupijuice_ > bbbb < _jupijuice_ > cccc < _jupijuice_ > 
Comments
In regular expressions you can use $ to match end of line:
sed 's/$/\n< _jupijuice_ >/' input.txt 
1 Comment
NeronLeVelu
no need of the cat, just give the file name to sed directly ;-).
\n in other sed than GNU will failed if in replacment pattern, you need a real new line in this case.sed 'a\ < _jupijuice_ >' YourFile append a line <...> after each line
2 Comments
josifoski
what is best is best → sourceforge.net/projects/anytextfile this is my program, needed this small sed command for dividing blocks, for books reading, tweets reading like from github.com/sferik/t etc.
NeronLeVelu
sorry, don't have access to your project code. Using a sed into another package is maybe not the best. I don't know lazarus code but ther is no code allowing text modfication as internal code ? Any instruction using regex manipulation will certainly suite your need
This should do:
awk '$0=$0"\n< _jupijuice_ >"' 