I am loving gulpjs, but am having an issue where my gulpfile.js is just getting really, really big.
I have searched pretty extensively and am having difficulty finding resources related to this, but is it possible to split a gulpfile.js up into multiple smaller js files just for organization?
Yes, you can do it to manage your tasks. For example if you have this file organization:
gulpfile.js -- tasks ---- test.js ---- dev.js You have to install de require-div module:
npm install require-dir --save-dev And, finally, you add this code to your gulpfile
var requireDir = require('require-dir'); var dir = requireDir('./tasks'); Hope it helps.
Regards.
I do it this way (I use coffeescript, but the theory is sound), similar to the above:
tasks = fs.readdirSync './gulp/tasks' tasks.forEach (task)-> require "./tasks/#{task}" if task.indexOf('coffee') >= 0 All it does is read the task folder and require all the files in it as long as they're .coffee files (which isn't 100% kosher, but it does avoid hidden dotfiles).
