I have a windows custom control with a picturebox and a button on it's default panel. This windows custom control will be added to a windows form. There is another windows form called form2. when the user double clicks on the custom control, it should load form2. in designer when i double clicked the custom control on the form, it creates a load() event for that custom control. But i need double click event, how this can be done?

here is the graphical view of what happens 
Here is code in the control
[DefaultEvent("DoubleClick")] public partial class cntrlImageLoader : UserControl { public cntrlImageLoader() { InitializeComponent(); } private void btnBrowse_Click(object sender, EventArgs e) { OpenFileDialog ofd = new OpenFileDialog(); ofd.InitialDirectory = Environment.SpecialFolder.MyPictures.ToString(); if (ofd.ShowDialog() == DialogResult.OK) { pbImage.Image = Image.FromFile(ofd.FileName); } } private void pbImage_Click(object sender, EventArgs e) { this.cntrlImageLoader_DoubleClick(pbImage, e); } private void cntrlImageLoader_Load(object sender, EventArgs e) { } private void cntrlImageLoader_DoubleClick(object sender, EventArgs e) { } } Here is the calling code on form1
private void cntrImLdrFront_DoubleClick(object sender, EventArgs e) { //this.cntrImLdrFront.pbImage.DoubleClick += new EventHandler(pbImage_DoubleClick); } FrmImageViewer f; // this is form2 private void pbImage_DoubleClick(object sender, EventArgs e) { f= new FrmImageViewer(); f.MdiParent = this.MdiParent; f.Show(); }
LoadPictureEventArgs