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Hello friends i have string like 

Android_a_b.pdf

i want to split it like Android_a_b and pdf

i try following code like 

String s="Android_a_b.pdf"; String[] parts = s.split("."); String part1 = parts[0]; String part2 = parts[1];

when i run above code it give me error like 

11-05 09:42:28.922: E/AndroidRuntime(8722): Caused by: java.lang.ArrayIndexOutOfBoundsException: length=0; index=0

at String part1 = parts[0]; line

any idea how can i solve it?

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You need to escape . using \

Eg:

String s="Android_a_b.pdf"; String[] parts = s.split("\\."); // escape . String part1 = parts[0]; String part2 = parts[1];

Now it will split by .

Split(regex) in Java

Splits this string around matches of the given regular expression.

This method works as if by invoking the two-argument split method with the given expression and a limit argument of zero. Trailing empty strings are therefore not included in the resulting array.

Keep in mind that

Parameters: regex - the delimiting regular expression

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4 Comments

It's also important to note that your error points out there is nothing in your Array. If you try to access [0] and get an index out of bounds then you can safely assume that there is something wrong with the split.
Exactly. Unescaped, the "." matches every character, so every character is a delimiter and the result of the split consists entirely of empty strings, none of which are included in the return value.
Pattern.quote will make your life easier: s.split(Pattern.quote(".")); (use import java.util.regex.Pattern)
When we have a input like "12.34..." split length is still 2. But if we have "12.34...5" split length is 5. Seems like when a number ends with more dot, that is not considered. But in my case I need that to be considered in length. Any Idea?