parsing XML in Python

Question

I have an XML that I would like to parse then send the result into a txt file.

The XML file is build from blocks like this one :

<rpc-reply message-id="12" xmlns="urn:ietf:params:xml:ns:netconf:base:1.0"> <user-stats> <allocated-user-count>10</allocated-user-count> <current-user-count>3</current-user-count> <max-active-user-count-24hrs>2</max-active-usercount- 24hrs> <min-active-user-count-24hrs>0</min-active-usercount- 24hrs> </user-stats> </rpc-reply>

All the blocks will start with and and with

I would like to remove all the tags and get the results by line and copy them in a text file. For example :

allocated user count <tab> current-user-count <tab> max-user-count 100 <tab> 1<tab> 2<tab> 100 <tab> 0<tab> 2<tab> (info taken from the second RPC block)

etc

Is there any way I can do this?

Anshul Goyal · Accepted Answer · 2014-11-14 17:32:36Z

You can use the xmltodict module for this.

You will need to install it using

pip install xmltodict

Once you've it, just do

import xmltodict data = xmltodict.parse(xmldata)

This will give you an early traversable python dict, which you can then use to get the values you want.

Qwertronix · Accepted Answer · 2014-11-14 17:38:13Z

Yes, there are ways you can do this.

The most accessible would be to use the XML Processing Modules, included in Python's standard library, to read the XML, and then use a text file object to output to the text file after doing your processing.

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