bitset to dynamic bitset

Question

I have a function where i use bitset.Now i need to convert it to a dynamic bitset.. but i don't know how. Can somebody help me ?

set<string> generateCandidates(set<string> ck,unsigned int k){ set<string> nk ; for (set<string>::const_iterator p = ck.begin( );p != ck.end( ); ++p){ for (set<string>::const_iterator q = ck.begin( );q != ck.end( ); ++q){ bitset<4> bs1(*p); bitset<4> bs2(*q); bs1|= bs2 ; if(bs1.count() == k){ nk.insert(bs1.to_string<char,char_traits<char>,allocator<char> >()); } } } return nk; }

Georg Fritzsche · Accepted Answer · 2010-04-26 02:47:31Z

3

The difference isn't that big:

boost::dynamic_bitset<> bs1(*p); boost::dynamic_bitset<> bs2(*q); bs1 |= bs2; if(bs1.count() == k){ std::string str; boost::to_string(bs1, str); nk.insert(str); }

answered Apr 26, 2010 at 2:47

Georg Fritzsche

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2 Comments

Potatoswatter Over a year ago

… and use dynamic_bitset instead of string. (dynamic_bitset implements operator<)

Georg Fritzsche Over a year ago

Agreed, using dynamic_bitset and converting to std::string only when neccessary would be better.

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