I need to process a list of emails, cut them and make the output with counter of iterations
MailList = [[email protected], [email protected], [email protected]] # I have a list with emails # I need to process them and get next output: "User%number% is email1" I'm using something like: for c in MailList: print('user'+ ' is '+c[0:7]) # what I need to insert here to get desirable counter for my output? You need to split the emails with @ :
>>> MailList = ['[email protected]', '[email protected]', '[email protected]'] >>> for i in MailList : ... print ('user'+ ' is {}'.format(i.split('@')[0]) ) ... user is email1 user is email2 user is email3 If I understand correctly, you want this:
MailList = ["[email protected]", "[email protected]", "[email protected]"] for index, value in enumerate(MailList): print('user {} is {}'.format(index, value.split("@")[0])) See the docs for details on enumerate.
using itertools.takewhile:
>>> import itertools >>> MailList = ['[email protected]', '[email protected]', '[email protected]'] >>> for x in MailList: ... print("user is {}".format("".join(itertools.takewhile(lambda x:x!='@',x)))) ... user is email1 user is email2 user is email3 using index:
>>> for x in MailList: ... print("user is {}".format(x[:x.index('@')])) ... user is email1 user is email2 user is email3 using find:
>>> for x in MailList: ... print("user is {}".format(x[:x.find('@')])) ... user is email1 user is email2 user is email3 