List file using ls command in Linux with full path [duplicate]

Question

Many will found that this is repeating questions but i have gone through all the questions before asked about this topic but none worked for me.

I want to print full path name of the certain file format using ls command so far i found chunk of code that will print all the files in the directory but not full path.

for i in io.popen("ls /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7"):lines() do if string.find(i,"%.*$") then print(i) end end

this will print out all the file in root diractory and subdiratory.

Output:

 0020111118223425.lvf 2012 2012 (2009).mp4 3 Idiots Aashiqui 2 Agneepath.mkv Avatar (2009) Captain Phillips (2013) Cocktail

I want output like:

 /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/0020111118223425.lvf [File in Root Directory] /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/2012/2012.mkv /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/2012 (2009).mp4 [File in Root Directory] /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/3 Idiots/3 Idiots.mkv /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Aashiqui 2/Aashiqui 2.mkv /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Avatar (2009)/Avatar (2009).mkv /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Captain Phillips (2013).mkv /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/Cocktail/Cocktail.mkv

EDIT: I have used this all but its not working with my code in LUA.

when I used with my code it displays wrong directory

for i in io.popen("ls -d $PWD/* /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7"):lines() do if string.find(i,"%.*$") then print("/mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/"..i) end end

is not finding files in "/mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7" insted its prints the machines root directory files.

Totoro · Accepted Answer · 2020-02-11 07:03:24Z

84

You can use

 ls -lrt -d -1 "$PWD"/{*,.*}

It will also catch hidden files.

edited Feb 11, 2020 at 7:03

answered Dec 7, 2014 at 6:48

Totoro

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6 Comments

Totoro Over a year ago

@user1640175 for i in io.popen("ls -lrt -d -1 /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/{*,.*}")

davemyron Over a year ago

It doesn't work when you don't have access to a directory and can't expand the *. (For example, sudo ls -d -1 /some/dir/i/cant/normally/access/*)

pevik Over a year ago

Please add quotas around $PWD ls -lrt -d -1 "$PWD"/{*,.*} (fixes directories with spaces).

rtx13 Over a year ago

Does not work for directories/paths with a lot of directory entries: -bash: /bin/ls: Argument list too long

grin Over a year ago

and actually this is not ls but the shell expanding the glob. As rtx13 mentioned this going to fail when the shell is unable to.

|

heemayl · Accepted Answer · 2017-07-04 03:52:42Z

66

You can try this:

ls -d $PWD/*

edited Jul 4, 2017 at 3:52

heemayl

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answered Dec 7, 2014 at 7:09

mgigirey

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3 Comments

user2188875 Over a year ago

ls -d "$PWD"/* to account for paths with spaces on them.

schreon Over a year ago

For empty directories, this throws No such file or directory. I would have expected to just see nothing like when doing ls on an empty directory, but no exception.

Nam G VU Over a year ago

why need -d ? for me just like this > $ ls pwd/*

score 30 · Accepted Answer · 2016-03-06 01:35:22Z

For listing everything with full path, only in current directory

find $PWD -maxdepth 1

Same as above but only matches a particular extension, case insensitive (.sh files in this case)

find $PWD -maxdepth 1 -iregex '.+\.sh'

$PWD is for current directory, it can be replaced with any directory

mydir="/etc/sudoers.d/" ; find $mydir -maxdepth 1

maxdepth prevents find from going into subdirectories, for example you can set it to "2" for listing items in children as well. Simply remove it if you need it recursive.

To limit it to only files, can use -type f option.

find $PWD -maxdepth 1 -type f

After trying all sorts of solutions, this is the only one I could find that would work 1)recursively while 2)referencing symlinks and 3)printing the entire path (which I need for | grep). Thanks!
This answer is basically what I use most of the time: find . -name fname*

Community · Accepted Answer · 2020-06-20 09:12:55Z

You could easily use the following to list only files:

ls -d -1 $PWD/*.*

the following to list directories:

ls -d -1 $PWD/**

the following to list everything (files/dirs):

ls -d -1 $PWD/**/*

More helpful options:

-d list directories not their content

-R recursive

-1 list one file per line

-l use long listing format

-a list all including entries starting with . and ..

-A list all but don't list implied . and ..

for more info, just type the following

ls --help

How is ls -d -1 $PWD/*.* printing files only? I have so many files w/o any file extension.

Paul Rougieux · Accepted Answer · 2020-11-18 16:17:01Z

Print the full path (also called resolved path) with:

realpath README.md

In interactive mode you can use shell expansion to list all files in the directory with their full paths:

realpath *

If you're programming a bash script, I guess you'll have a variable for the individual file names.

Thanks to VIPIN KUMAR for pointing to the related readlink command.

score 3 · Accepted Answer · 2015-03-25 03:05:00Z

This prints all files, recursively, from the current directory.

find "$PWD" | awk /.ogg/ # filter .ogg files by regex find "$PWD" | grep .ogg # filter .ogg files by term find "$PWD" | ack .ogg # filter .ogg files by regex/term using https://github.com/petdance/ack2

JohnnyC · Accepted Answer · 2024-03-10 22:12:24Z

The simpliest way is to do it with find. And if you want to list certian types of files just use grep after the |

ie to display only mp3 files within a folder

find /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7 | grep mp3

desertnaut · Accepted Answer · 2024-03-11 02:28:00Z

How about:

 du -a [-b] [--max-depth=N]

That should give you a file and directory listing, relative to your current location. You will get sizes as well (add the '-b' parameter if you want the sizes in bytes). The max-depth parameter may be necessary to "encourage" du to dive deeply enough into your file structure -- or to keep it from getting carried away.

desertnaut · Accepted Answer · 2024-03-11 02:28:17Z

1

try this:

readlink -f file.txt

edited Mar 11, 2024 at 2:28

desertnaut

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answered Apr 17, 2020 at 21:02

VIPIN KUMAR

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Comments

Jose Rey · Accepted Answer · 2014-12-07 06:54:23Z

There is more than one way to do that, the easiest I think would be:

find /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7

also this should work:

(cd /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7; ls | xargs -i echo `pwd`/{})

Frits · Accepted Answer · 2017-07-04 06:02:23Z

0

This worked for me:

ls -rt -d -1 $PWD/{*,.*}

edited Jul 4, 2017 at 6:02

Frits

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answered Jul 3, 2017 at 22:52

HARSH NILESH PATHAK

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1 Comment

mynetx Over a year ago

Could you elaborate on the flags used in your code?

omen23 5 · Accepted Answer · 2019-01-14 21:01:54Z

you just want the full path why not use the utility meant for that a combination of readlink and grep should get you what you want

grep -R '--include=*.'{mkv,mp4} ? | cut -d ' ' -f3 | xargs readlink -e # the question mark should be replaced with the right pattern - this is almost right # this is probably the best solution remove the grep part if you dont need a filter find <dirname> | grep .mkv | xargs readlink -e | xargs ls --color=auto # only matroska files in the dir and subdirs with nice color - also you can edit ls flags find /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7 | grep .mkv find /mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7 | xargs grep -R '--include=*.'{mkv,mp4} . | cut -d ' ' -f3 # I am sure you can do more with grep readlink -f `ls` # in the directory or

John Singac · Accepted Answer · 2022-07-26 00:50:25Z

0

If you want recursive listing of absolute pathnames within a subdirectory tree, use du and pipe into cut.

edited Jul 26, 2022 at 0:50

answered Jul 26, 2022 at 0:48

John Singac

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1 Comment

Community Over a year ago

As it’s currently written, your answer is unclear. Please edit to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers in the help center.

desertnaut · Accepted Answer · 2024-03-11 02:28:43Z

I have had this issue, and I use the following :

ls -dl $PWD/* | grep $PWD

It has always got me the listing I have wanted, but your mileage may vary.

desertnaut · Accepted Answer · 2024-03-11 02:28:55Z

-1

The ls command will only print the name of the file in the directory. Why not do something like

print("/mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/" + i)

This will print out the directory with the filename.

edited Mar 11, 2024 at 2:28

desertnaut

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answered Dec 7, 2014 at 6:40

yxre

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2 Comments

Prakash.DTI Over a year ago

This will not work with subdiractory. adn also i want implement in lua so i think you are telling me to do like print("/mnt/mediashare/net/192.168.1.220_STORAGE_1d1b7/"..i)

yxre Over a year ago

Your code was using a string literal. I only copied and pasted it. It would be trivial to make the changes to your lua script that would allow you to call this on any directory, and get your desired results.

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