How to tell if a list inside a dict is empty

Question

I have a movietimes={}

It a dict I make by this code:

for i in Showtime.objects.filter(movie_id=movieid,theater_id=theaterid,datetime__range=(today,tomorrow))): if i.mvtype not in movietimes: movietimes[i.mvtype] = [] if not i.movietime > today : movietimes[i.mvtype].append(i.movietime.strftime('%Y-%m-%dT%H:%M:%S.%fZ')) if not movietimes : #this have bug for i in Showtime.objects.filter(movie_id=movieid,datetime__range=(yesterday,today)): if i.mvtype not in movietimes: movietimes[i.mvtype] = [] movietimes[i.mvtype].append(i.movietime.strftime('%Y-%m-%dT%H:%M:%S.%fZ')) return movietimes

result like this:

 "Times": { "ONE: [ "2014-12-24T10:40:00.000000Z", "2014-12-24T12:45:00.000000Z", "2014-12-25T14:50:00.000000Z" ] }

I want to ask how can't I judge that if the [] in the 'ONE' part is null ??

I can't use if not movietimes={}: ,because there is u'ONE': [] in the dict

I have to judge the first list in the dict is empty . And there are many types u'ONE',u'TWO',u'Three'

they are catch by i.mvtype

{u'ONE': []} {u'TWO': []} {u'Three': []}

Please help me ,Thank you

Wait, what do you mean by "the first list in the dict"? dicts aren't ordered. — senshin
– senshin, Commented Dec 24, 2014 at 1:22
the [] part in {u'Three': []} a guy answer my question ,I can use if not any(movietimes.values()) but it's deleted — user2492364
– user2492364, Commented Dec 24, 2014 at 1:31

Padraic Cunningham · Accepted Answer · 2014-12-24 01:29:06Z

if not movietimes["Times"]["ONE"]: # you have empty list

That is presuming by first you mean the key ONE as dicts are not ordered

If you want to see if there is any empty list and your dict is like below:

movietimes = {"Times":{"ONE":[2],"TWO":[]}} for val in movietimes["Times"].itervalues(): if not any(x for x in val): # you have empty list

so I have to type ["ONE"] ?? can it be catch by code . because I have many of them ["ONE"] ["Two"] ["Three"] ....

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