I am trying to run a python script first.py from within another python script second.py.
second.py contains the statement os.system("python first.py").
first.py : default open App was notepad previously. But, I changed Default Program to python.exe and now nothing happens. first.py doesn't even run.
Can anyone help?
If all the scripts are from "trusted" sources, you could safely use execfile().
with open('second.py', 'w') as f: f.write('print "hello world"') try: execfile('second.py') # -> hello world except Exception as e: # could also be "pass", "time.sleep()", etc print 'exception {} occurred'.format(e) print 'continuing on...' One advantage of this is that it's independent of which Default Program is associated with Python scripts. Also the argument to execfile() can be the complete path to a script in another folder, for example:
execfile('c:/path/to/different/directory/first.py') 
Exception, shown.Instead of using os.system(), a clean way to execute another script is to import it as a module:
import second The will cause "second.py" to be executed.
>>> with open('test.py', 'w') as f: f.write('print "hello world"') ... >>> import test hello world 
You can run your another python program using subprocess.call module.
import subprocess subprocess.call("second.py", shell=True) 
python.exe?