Splitting a nested dictionary based on value of nested key

Question

I have a nested dictionary that I would like to split based on the value of end qty. I would like to only keep keys in which 'end qty' == 0. I believe it can be done easily with dictionary comprehension, but I can't quite get it right.

import datetime d = { 'ID1' : {'start qty': 13 , 'end qty': 40}, 'ID2' : {'start qty': 10 , 'end qty': 0}, 'UD3' : {'start qty': 30 , 'end qty': 30}, 'ID4' : {'start qty': 20 , 'end qty': 0}, } print { k:v for k, v in d.items() if ['end qty'] == 0 }

if v['end qty'] == 0?

Ashwini Chaudhary
– Ashwini Chaudhary

2015-01-22 21:55:19 +00:00
Commented Jan 22, 2015 at 21:55 — Ashwini Chaudhary
– Ashwini Chaudhary, Commented Jan 22, 2015 at 21:55

zer0uno · Accepted Answer · 2015-01-22 21:56:06Z

1

Just add v in the print statement, in this way

print { k:v for k, v in d.items() if v['end qty'] == 0 }

answered Jan 22, 2015 at 21:56

zer0uno

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Malik Brahimi · Accepted Answer · 2015-01-22 21:56:18Z

1

Try this line instead:

print { k:v for k, v in d.items() if v['end qty'] == 0 }

answered Jan 22, 2015 at 21:56

Malik Brahimi

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