I start with tree plots:
df = pd.DataFrame([1,20,3],[2,30,4],[3,40,5],columns=['mean','size','stat']) fig,[ax1,ax2,ax3] = plt.subplots(1, 3, sharey=True) ax1.barh(np.arange(len(df)),df['mean'].values, align='center') ax2.barh(np.arange(len(df)),df['size'].values, align='center') ax3.barh(np.arange(len(df)),df['stat'].values, align='center') Is there a way to rotate the x axis labels on all three plots?
When you're done plotting, you can just loop over each xticklabel:
for ax in [ax1,ax2,ax3]: for label in ax.get_xticklabels(): label.set_rotation(90) You can do it for each ax your are creating:
ax1.xaxis.set_tick_params(rotation=90) ax2.xaxis.set_tick_params(rotation=90) ax3.xaxis.set_tick_params(rotation=90) or you do it inside a for before showing the plot if you are building your axs using subplots:
for s_ax in ax: s_ax.xaxis.set_tick_params(rotation=90) 
df = pd.DataFrame([1,20,3],[2,30,4],[3,40,5],columns=['mean','size','stat']) fig,[ax1,ax2,ax3] = plt.subplots(1, 3, sharey=True) plt.subplot(1,3,1) barh(np.arange(len(df)),df['mean'].values, align='center') locs, labels = xticks() xticks(locs, labels, rotation="90") plt.subplot(1,3,2) barh(np.arange(len(df)),df['size'].values, align='center') locs, labels = xticks() xticks(locs, labels, rotation="90") plt.subplot(1,3,3) barh(np.arange(len(df)),df['stat'].values, align='center') locs, labels = xticks() xticks(locs, labels, rotation="90") Should do the trick.
Here is another more generic solution: you can just use axes.flatten() which will provide you with much more flexibility when you have higher dimensions.
for i, ax in enumerate(axes.flatten()):
sns.countplot(x= cats.iloc[:, i], orient='v', ax=ax) for label in ax.get_xticklabels(): # only rotate one subplot if necessary. if i==3: label.set_rotation(90) fig.tight_layout()
