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I am trying to loop though an array in bash. The array is "AARON" currently that array fills index 0 with AARON. I want to be behave as such

ara[0] = A
ara[1] = A
ara[2] = R
ara[3] = O
ara[4] = N

My script currently looks like this.

 #!/bin/bash declare count declare -a ara=(AARON) for name in {A..Z} do count=$((count++)) for char in ${ara[*]} do if [[ ${ara[char]} -eq $name ]] echo ${ara[char]} # for debugging purposes. then sum=$((sum + count)) fi done done echo $sum #for debugging purposes.

Normally I would achieve this by setting a custom IFS but I don't know how I would do that for each character of string.

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2 Answers 2

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You want = not -eq for string comparison.

Your echo ${ara[char]} line is part of your if test not part of the if body.

Your count=$((count++)) assignment doesn't work correctly (it always sets count to zero) you want ((count++)) or count=$((++count)) instead.

You can use ${strvar:pos:count} to get parts of a string.

So something like this:

#!/bin/bash declare count declare -a ara=(AARON) for name in {A..Z} do ((count++)) for ((i=0; i<=${#ara[0]}; i++)) do echo ${ara[0]:i:1} # for debugging purposes. if [[ ${ara[0]:i:1} = $name ]] then sum=$((sum + count)) fi done done echo $sum # for debugging purposes.
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1 Comment

Nicely done; in the spirit of ((count++)): sum=$((sum + count)) could be simplified to ((sum += count)).
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I would do something like this:

declare count declare -a ara=(A A R O N) for name in {A..Z} do for character in ${ara[*]} do if [[ ${character} == ${name} ]] then echo ${character} '=' ${name} # for debugging purposes. let 'sum=sum+1' fi done done echo $sum #for debugging purposes.

You could add spaces into every letter to convert AARON in a bash array. Moreover, you could use "let" to inrease the counter.

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