Adding current date and time into a bash script echo command

Question

I have a script that takes many hours to finish. I would like to add the current date and time to an echo command that prints to the screen every time a step completes.

So my command creates and inserts about 20 databases. some databases take several hours to insert so I would like to print the time each step finishes to the screen so you can know where in the process the restore is. Here is what I have so far.

#!/bin/sh for DB_File in *.sql ; do mysqladmin create ${DB_File%%-*} echo ${DB_File%%-*} has been created. date +%x_%X mysql ${DB_File%%-*} < $DB_File echo $DB_File inserted into database. date +%x_%X done

Either put the date command on its own line or use $(date +%x_%X) to substitute the command output on the echo line. — Etan Reisner
– Etan Reisner, Commented Mar 16, 2015 at 15:48
Thanks if I use echo $(date) it works. the $(date +%x_%X) gives an error "date: invalid date ‘=%x_%X’" but I can work with the output from just date. Thank You. — Rick Bonney
– Rick Bonney, Commented Mar 16, 2015 at 17:15
Just date. No need for echo $(date) it is pointless. And =%x_%X is not the same as +%x_%X. =) — Etan Reisner
– Etan Reisner, Commented Mar 16, 2015 at 17:16

Würgspaß · Accepted Answer · 2015-03-19 21:24:55Z

This should work:

for DB_File in *.sql ; do mysqladmin create ${DB_File%%-*} echo ${DB_File%%-*} has been created. `date "+%F %T"` mysql ${DB_File%%-*} < $DB_File echo $DB_File inserted into database. `date "+%F %T"` done

By using backquotes the result of date command is used. If you need another date format, just see what "date --help" has on offer.

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