How are $LOAD_PATH and $: different?

Question

I needed to know what was in my Ruby load path, so I did this:

$ ruby -e "puts $LOAD_PATH"

It didn't print anything out, which I didn't expect. So I tried this:

$ ruby -e "puts $:" /usr/local/lib/site_ruby/1.8 /usr/local/lib/site_ruby/1.8/i486-linux /usr/local/lib/site_ruby/1.8/i386-linux /usr/local/lib/site_ruby /usr/lib/ruby/vendor_ruby/1.8 /usr/lib/ruby/vendor_ruby/1.8/i486-linux /usr/lib/ruby/vendor_ruby /usr/lib/ruby/1.8 /usr/lib/ruby/1.8/i486-linux /usr/lib/ruby/1.8/i386-linux .

Why does the second one give me the expected output and the first one doesn't? Shouldn't they be the same? I just tried it in irb, and I got the results I expected.

This is my Ruby version, in case it makes a difference:

$ ruby --version ruby 1.8.7 (2008-08-11 patchlevel 72) [i486-linux]

P Shved · Accepted Answer · 2010-05-27 15:39:23Z

8

They are not. Try running this command:

$ ruby -e 'puts $LOAD_PATH'

which doesn't make shell expand $LOAD_PATH due to use of ' instead of ".

answered May 27, 2010 at 15:39

P Shved

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1 Comment

Benjamin Oakes Over a year ago

Gah! That makes perfect sense. I guess this is the first time I've used a global when doing ruby -e. :)

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