Using Android Volley to post an array to PHP

Question

This is how I post the values with Volley:

@Override protected Map<String, String> getParams() { JSONObject jsonObjectMembers=new JSONObject(); for (int i=0; i<arr_added_userids.size(); i++) { try { jsonObjectMembers.put("params_"+i,arr_added_userids.get(i)); } catch (JSONException e) { e.printStackTrace(); } } Map<String, String> params = new HashMap<String, String>(); params.put("host", session_userid); params.put("params",jsonObjectMembers.toString()); return params; }

This is what I tried:

foreach($_POST['params'] as $key => $value) { try { $stmt = $conn->prepare("INSERT INTO CREWMEMBERS (CREWID, MEMBER) VALUES (:crewid, :member)"); $query_params = array( ':crewid' => $crewid, ':member' => $value ); $stmt->execute($query_params); $response["success"] = 1; } catch(PDOException $e) { //echo 'ERROR: ' . $e->getMessage(); $response["success"] = 3; } }

I always get org.json.JSONException: Value <br of type java.lang.String cannot be converted to JSONObject

When I send $_POST['params'] to myself in email to see how it looks like, I get

{"params_0":"000000000284","params_1":"000000000229","params_2":"000000000081"}

How do I handle these items separately?

' always get org.json.JSONException: Value <b'. Where? I see no code that would produce such an error. — greenapps
– greenapps, Commented Apr 5, 2015 at 20:02
Which org.json jar are you using? There seem to be several around with that name. Also how can the PHP code (at least in the way you ask this question) throw a Java exception? — Norbert
– Norbert, Commented Apr 6, 2015 at 2:14

Renatas · Accepted Answer · 2015-05-19 08:39:37Z

1

I have just faced the same problem. My solution:

Map<String, String> params = new HashMap<String, String>(); params.put("params[0]", "a"); params.put("params[1]", "b"); params.put("params[2]", "c");

answered May 19, 2015 at 8:39

Renatas

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erdomester Over a year ago

I don't think this would help. I solved this long ago but what the code is missing now is the parameters from the getParams() part.

Robert · Accepted Answer · 2016-03-10 10:47:08Z

0

Map<String, String> params = new HashMap<String, String>(); params.put("params[0]", "a"); params.put("params[1]", "b"); params.put("params[2]", "c");

edited Mar 10, 2016 at 10:47

Robert

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answered Mar 10, 2016 at 10:43

Bhandari

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1 Comment

Scriptable Over a year ago

Could you provide a little more information in this answer for reference. Maybe why this way is the best option, what is it doing differently from the op that fixes the issue?.

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