Swift, a function defined in super class that returns the class name of subclass when called from a subclass object

Question

In Objective-C I can do this:

@interface MyManagedObjectSuperClass : NSManagedObject +(NSString*)entityName; @end @implementation +(NSString*)entityName { return NSStringFromClass([self class]) } @end

With this base class, all my other NSManagedObjects can inherit from MyManagedObjectSuperClass. I can get the entity name by calling +entityName, since there is polymorphism, in subclasses, NSStringFromClass([self class]) returns the class name of subclass.

So my question is, can I do this in Swift?

possible duplicate of Get class name of object as string in Swift — bjtitus
– bjtitus, Commented Apr 10, 2015 at 16:08
@bjtitus it's not a duplicate, I need to get it from a type instead of an instance, and I need polymorphism — MeloS
– MeloS, Commented Apr 10, 2015 at 16:19
NSStringFromClass() works in Swift as well. See stackoverflow.com/a/27112385/1187415 for an example. — Martin R
– Martin R, Commented Apr 10, 2015 at 16:20

Community · Accepted Answer · 2017-05-23 11:52:40Z

In a class method of an NSObject subclass, both

toString(self) NSStringFromClass(self)

return a string containing the class name (including product module name) of the actual subclass on which the method is called.

See How can I create instances of managed object subclasses in a NSManagedObject Swift extension? for an example how to extract the Core Data entity name from the full class name.

werediver · Accepted Answer · 2016-05-02 09:15:51Z

Is this straightforward approach what you need?

class Base { class func typeName() -> String { return "\(self)" } } class X: Base {} print(Base.typeName()) // Base print(X.typeName()) // X

Antonio · Accepted Answer · 2015-04-10 16:11:27Z

You can use dynamicType to obtain the class name (inclusive of the module name), and string interpolation to convert it to a string:

class Class1 { var entityName: String { return "\(self.dynamicType)" } }

The most obvious difference is that it's an instance and not a static property/method - that's probably a limitation in your case, as I presume you want to obtain the name from the type and not an instance of it.

Yes, you are right, I need to get the name from a type instead of an instance

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