Sorting list by values

Question

I'm trying to sort a dictionary by values but my code has been erroring. I have three files consisting of scores (in the format "Bob:4", with line breaks between each score.

for k in d.keys(): nlist = d[k][-3:] for v in nlist: nlist2 = max(nlist) sortd = sorted(nlist2.items(), key=lambda x: x[1]) print('{}: {} '.format(k, sortd))

This resulted in error "AttributeError: 'list' object has no attribute 'items'".

What is causing this error?

as @itzmeontv implies, put a print(d) in before your for k loop to make sure you have what you think you have — paddyg
– paddyg, Commented Apr 23, 2015 at 8:32
Sorry, I made a mistake. I'm trying to sort the values of nlist2 (the maximum for each user) and then print them out in a list, with the names next to them (in order of highest to lowest)# — DasKapital
– DasKapital, Commented Apr 23, 2015 at 8:32
To be clear: you want to go through the whole list of k in d and find the max of last three entries in d[k]. Then put that in a new dictionary, then sort that and finally print it. Is that right? — paddyg
– paddyg, Commented Apr 23, 2015 at 9:05

U2EF1 · Accepted Answer · 2015-04-23 08:30:12Z

2

Try it with sortd = sorted(nlist, key=lambda x: x[1]) and see if that gets what you wanted.

answered Apr 23, 2015 at 8:30

U2EF1

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paddyg · Accepted Answer · 2015-04-23 09:14:49Z

for revised question you could:

nlist2 = {k:max(d[k][-3:]) for k in d} sortd = sorted(nlist2.items(), key=lambda x: x[1]) for a in sortd: print('{}: {} '.format(a[0], a[1]))

or use -x[1] if you want highest first

amow · Accepted Answer · 2015-04-23 08:30:05Z

0

sortd = sorted(nlist.items(), key=lambda x: x[1])

This code here use nlist but it is a list according to nlist = d[k][-3:]

answered Apr 23, 2015 at 8:30

amow

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2 Comments

amow Over a year ago

@Morb The original code have an error msg here, and I just answer with the reason.

Morb Over a year ago

Sorry, I'm mixing up nlist and nlist2 here, he was trying to sort nlist2.items() which is an int

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