Print out the last match of a regex

In case you need to get some substring at the end that is preceded by similar substrings, you need to make sure the regex engine has already consumed as many characters before your required match as possible.

Also, you have a ^ in your pattern that means beginning of a string. Thus, it starts matching from the very beginning.

You can achieve what you want with just lastIndexOf and substring:

System.out.println(str.substring(str.lastIndexOf("http://"))); 

Or, if you need a regex, you'll need to use

String pattern = ".*(http://.*?\\.m3u8)$"; 

and use math.group(1) to print the value.

Sample code:

import java.util.regex.*; public class HelloWorld{ public static void main(String []args){ String str = "http://xxxxx-f.akamaihd.net/i/world/open/20150426/1370235-005A/EPISOD-1370235-005A-016f1729028090bf_,892,144,252,360,540,1584,2700,.mp4.csmil/index_0_av.m3u8" + "EXT-X-STREAM-INF:PROGRAM-ID=1,BANDWIDTH=2795000,RESOLUTION=1280x720,CODECS=avc1.64001f, mp4a.40.2" + "http://xxxxx-f.akamaihd.net/i/world/open/20150426/1370235-005A/EPISOD-1370235-005A-016f1729028090bf_,892,144,252,360,540,1584,2700,.mp4.csmil/index_6_av.m3u8"; String rx = ".*(http://.*?\\.m3u8)$"; Pattern ptrn = Pattern.compile(rx); Matcher m = ptrn.matcher(str); while (m.find()) { System.out.println(m.group(1)); } } } 

Output:

http://xxxxx-f.akamaihd.net/i/world/open/20150426/1370235-005A/EPISOD-1370235-005A-016f1729028090bf_,892,144,252,360,540,1584,2700,.mp4.csmil/index_6_av.m3u8 

Also tested on RegexPlanet