{int num1 = 5; int num2 = 6; int num3; num3 = ++num2 * num1 / num2 + num2; System.out.println(num3);} //12 The compiler gives the num3 = 12, but how do I get that value? when I try to get that num3 value I got 6(by without using compiler). Both value of num2++ and ++num2 gives the same, but when I use following code it gives a different value. Why I got different values. what are the steps for get those num3 values (without using compiler?)
num3 = num2++ * num1 / num2 + num2; //11 Both increment operation num++ and ++num will result into num=num+1 there is only difference between the order of assignment and increment operations.
num++(post-increment) -> first num is used and then incremented ++num(pre-increment) -> first num is incremented and then used
You code prints 12 when I tested.
public static void main(String[] args) { int num1 = 5; int num2 = 6; int num3; num3 = ++num2 * num1 / num2 + num2; System.out.println(num3); } I will suggest you to make use of brackets as it will increase readability as well.
If you do:
int num2 = 6; System.out.println(num2++); It will print 6, and then change num2 to 7. But if you do:
int num2 = 6; System.out.println(++num2); It will change num2 to 7 and then print 7. So:
num3 = ++num2 * num1 / num2 + num2; num3 = 7 * 5/ 7 + 7 num3 = 35/7 + 7 num3 = 12 