first time I'v posted here but I must know what's wrong with this simple peace of code:
#include <iostream> using namespace std; int main() { double test = (1 / 2) * 2; cout << test << endl; return 0; } when ever I run this the code it displays 0, should I be casting something, it happens regardless of what compiler I use and it returns even stranger results if the '1' is divided be some form of decimal.
Because in integer maths 1 / 2 == 0 and 0 * 2 == 0.
Try with 1.0 and 2.0 instead.
In (1 / 2) both the 1 and 2 are integers which means that the result is also an integer. This means the expression returns 0. 0 * 2 is 0.
To get the result you want, try (1.0 / 2.0)
.0 only one side.If you want to get right result you need to write:
#include <iostream> using namespace std; int main() { double test = ((double)1 / 2) * 2; cout << test << endl; return 0; } 
You're using int instead of double.
Fixing...
#include <iostream> using namespace std; int main() { double test = (1.0 / 2.0) * 2.0; cout << test << endl; return 0; } 
ints. And by default, all numbers areints.