I have some string, which is some path C:\A\B\C\D\ How can I get the folder name, say "A" or "B" or other needed. I have solution only for "D":
@echo off setlocal enabledelayedexpansion FOR /f %%i IN ("C:\A\B\C\D\") DO ( set parent=%%~dpi for /F "tokens=*" %%f in ("!parent:~0,-1!") do echo %%~nf ) Next code snippet splits a string to substrings delimited with the \ backslash character. Works with or without a trailing backslash, with or without blank space(s) in a string (path). Note proper quoting in set commands:
@ECHO OFF SETLOCAL enableextensions set "fullpath=C:\Aa\B b\Cc\D d\" set "to_parse="%fullpath:\=" "%"" for %%G in (%to_parse%) do ( echo %%~G %%G ) Output:
==>30285354.bat C: "C:" Aa "Aa" B b "B b" Cc "Cc" D d "D d" "" ==> Resources (required reading):
%~G etc. special page) Command Line arguments (Parameters)Your question is not clear ("other folder needed" is not a specification) so I assumed you want to separate all folders into array elements, so any desired folder can be get via its index.
@echo off setlocal EnableDelayedExpansion set "string=C:\A\B\C\D\" rem Separate all folders in the string into "folder" array set i=-1 for %%a in ("%string:\=" "%") do ( if %%a neq "" ( set /A i+=1 set "folder[!i!]=%%~a" ) ) rem Show some folders echo The first folder: %folder[1]% echo The second folder: %folder[2]% echo The last folder: !folder[%i%]! For further details on arrays in Batch files, see this post.
