String regex for replacement

Question

I have this pattern (N|S)(..)(W|E)(...).hgt. I need to replace this with (N|S)(..)(W|E)(...).xyz.hgt.

So as an example if I have N06E072.hgt I would need to replace this with N06E072.xyz.hgt. This is for a set of files where the values could change depending on latitude and longitude. The way I have coded this is to extract the latitude and the value and the corresponding longtitude and it's value. Concatenate the characters and then do a simple replace of these set of characters with the new set of characters. Is there a better way of doing this ?

private static final Pattern filePattern = Pattern.compile("(N|S)(..)(W|E)(...).*") Matcher matcher = filePattern.matcher(file.getName()); if (matcher.matches()) { String latDir = matcher.group(1); lat = Integer.parseInt(matcher.group(2)); if (latDir.equalsIgnoreCase("s")) lat *= -1; String lonDir = matcher.group(3); lon = Integer.parseInt(matcher.group(4)); if (lonDir.equalsIgnoreCase("w")) lon *= -1; }

Why can't you use : replaceAll("\\.", ".xyz.")?. This replaces N06E072.hgt with N06E072.xyz.hgt — TheLostMind
– TheLostMind, Commented May 19, 2015 at 8:08
If it works and you're searching for a better solution, you should have posted it on codereview.stackexchange.com — halloei
– halloei, Commented May 19, 2015 at 8:09

halloei · Accepted Answer · 2015-05-19 08:16:52Z

1

I'd do it like this:

String s = "N06E072.hgt".replaceAll("([NS]{1}.{2}[WE]{1}.{3})\\.(.{3})", "$1.xyz.$2");

answered May 19, 2015 at 8:16

halloei

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