How can I find a string which includes quotation marks with grep? I tried a backslash to escape but this doesn't work.
For example search for the string "localStorage['api']". I tried:
grep -r "localStorage['api']" /path grep -r "localStorage[\'api\']" /path Your escaping is OK. The problem lies in the [], that grep understands as regular expressions. Thus, you need to somehow tell it to treat the string as literal. For this we have -F:
grep -F "localStorage['api']" file $ cat a hello localStorage['api'] and blabla bye $ grep -F "localStorage['api']" a hello localStorage['api'] and blabla From man grep:
-F, --fixed-strings
Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched.