XSLT - conditionally check element exist in Xpath

Question

I have a xml like follows,

<doc> <a> <b></b> </a> <a></a> <a> <b></b> </a> <a> <c></c> </a> <a></a> </doc>

what i need to do is if <a> has a  child (one or more) add <end> tag just before the end of the <a>node. if <a> has not  child do nothing.

so the result xml should be,

 <doc> <a> <b></b> <end></end> </a> <a></a> <a> <b></b> <b></b> <end></end> </a> <a> <c></c> </a> <a></a> </doc>

I cannot think about a way that how I should conditionally check in xpath to check if  child is existing or not in <a>.

I cannot use,

 <xsl:template match="a//b"> <xsl:copy> <xsl:apply-templates select="@* | *"/> <end></end> </xsl:copy> </xsl:template>

this adds <end> nodes to every  node.

Any suggestions how can I do this?

Thanks in advance

har07 · Accepted Answer · 2015-07-23 09:06:24Z

You can use a[b] to match <a> that has one or more child  :

<xsl:template match="a[b]"> <xsl:copy> <xsl:apply-templates select="@* | *"/> <end></end> </xsl:copy> </xsl:template>

or maybe a[.//b] if you rather meant to match <a> that has one or more descendant .

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