How to set the prototype of a function? [duplicate]

Question

Something like this, but not using __proto__:

var o = { i :2 }; var f1 = function(){ alert(f1.i); } f1.__proto__ = o; o.i = 3; f1(); //3

When I see such questions I always wonder: why do you people intentionally try to make your code as hard for understanding and maintenance as possible? — zerkms
– zerkms, Commented Aug 21, 2015 at 7:53
@D_Pavel: You're trying to set the internal prototype of a function object that doesn't yet exist? — Bergi
– Bergi, Commented Aug 21, 2015 at 8:27
@D_Pavel: why "like this, but not using __proto__"? What are you trying to do here in the first place, what is your use case? — Bergi
– Bergi, Commented Aug 21, 2015 at 8:28

NiRUS · Accepted Answer · 2015-08-21 08:07:59Z

0

One method is using bind API. So your Javascript looks like this

var o = {i :2}; var f1 = function(){ alert(this.i); }.bind(o) o.i = 3; f1(); //3

answered Aug 21, 2015 at 8:07

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2 Comments

bind not set the __proto__

@D_Pavel and in your question you did not ask to set it.