Are there any standard ways of marking a function argument as unused in JavaScript, analogous to starting a method argument with an underscore in Ruby?
7 Answers
Just so we have an example to work from, this is fairly common with jQuery's $.each where you're writing code that doesn't need the index, just the value, in the iteration callback and you're using this (which jQuery also sets to the value) for something else:
$.each(objectOrArrayLikeThing, (_, value) => { // Use `value` here }); (Yes, $.each passes arguments to the callback backward compared to the JavaScript standard forEach.)
Using _ is the closest I've seen to a standard way to do that, yes, but I've also seen lots of others — giving it a name reflective of its purpose anyway (index), combining those (_index), calling it unused, etc.
If you need to ignore more than one parameter, you can't repeat the same identifier (it's disallowed in strict mode, which should be everyone's default and is the default in modules and class constructs), so you have do things like _0 and _1 or _ and __, etc. I've almost never had to do that, but when I have, I've used a name indicating what the parameter's value would be (_index for the $.each example, for instance).
4 Comments
(_0, _1, value) or (in my case) (unused0, unused1, value). I've also seen (_, __, value) but...yikes. :-) There was a strawman proposal to allow blank parameter names once upon a time but it never went anywhere.function (_, _, a) { … } (of course inside the function the variable _ only contains the second passed argument) but there's no error and the function is created (and works) just fine.class constructs.)Using destructuring assignment, one can do:
function f(...[, , third]) { console.log(third); } f(1, 2, 3); 1 Comment
_: Variable name _ must match one of the following formats: camelCase, PascalCase, UPPER_CASEWith browsers supporting destructuring one can do:
function ({}, {}, value) { // console.log(value) } Which is kind of neat in that it avoids the problem of multiple arguments having the same name and also won't create problems with libraries that assign methods to _ (lodash, underscore, etc.).
One problem with this approach is that unused arguments of type undefined or null will throw.
For undefined one solution is to use default parameters:
function ({}={}, {}={}, value) { // console.log(value) } Sadly no such easily applied solution for null.
4 Comments
undefined or null.function ({}={}, {}={}, value) { ... } helps here, but it becomes messy...(function({}={}){})(0) or var {a}=0 will throw.How about using the function arguments object?
function third() { const [,,thirdArg] = arguments; return thirdArg; } console.log(third(1,2,3)); 1 Comment
There isn't a "standard"/"official" syntax, but there're a few options for skipping the unused arguments (from most to least recommended):
- Prefix its name with an underscore, e.g. "
(arg1, _arg2, arg3, _arg4, arg5) => {...}" - Use a destructured array, e.g. "
(...[, , arg3, arg4]) => {...}" - Destruct each into an empty object, e.g. "
(arg1, {}, {}, arg4) => {...}", if it'sundefined(not includingnull), add default assignment, e.g. "(arg1, {}={}, {}={}, arg4) => {...}" - Replace it with underscore(s), and increment number of underscores for each one, e.g. "
(arg1, _, __, ___, arg5) => {...}"
_that's being used.