Regex to allow only number between 1 to 12
I am trying (12)|[1-9]\d? but its not working, please help as i am new to regular expression
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5 Answers
Something like
^([1-9]|1[012])$ ^Anchors the regex at start of the string[1-9]Matches1to9|Alternation, matches the previous match or the following match.1[012]Matches10,11, or12$Anchors the regex at the end of the string.
2 Comments
Jaison James
Nice example!!, How could use this with a dynamic value, in the sense maybe it's 30 - 300 or 50 - 3500 etc
roschach
Probably it is better:
^(1[012]|[1-9])$ because so that if it isn't a double digit is for sure a single digit, whereas with the answer, it can find a digit of a double digit. In Python I noticed that for 10 it was returning 1 for example.Here's some readymade regex expressions for a bunch of different numbers within a certain range:
| Range | Label | Regex |
|---|---|---|
| 1 to 12 | hour / month | 1[0-2]|[1-9] |
| 1 to 24 | hour | 2[0-4]|1[0-9]|[1-9] |
| 1 to 31 | day of month | 3[01]|[12][0-9]|[1-9] |
| 1 to 53 | week of year | 5[0-3]|[1-4][0-9]|[1-9] |
| 0 to 59 | min / sec | [1-5]?[0-9] |
| 0 to 100 | percentage | 100|[1-9]?[0-9] |
| 0 to 127 | signed byte | 12[0-7]|1[01][0-9]|[1-9]?[0-9] |
| 32 to 126 | ASCII codes | 12[0-6]|1[01][0-9]|[4-9][0-9]|3[2-9] |
Comments
Try something like this:
^(1[0-2]|[1-9])$ 1[0-2] : first charcter must be 1 and second character can be in range from 0 to 2
[1-9] : numbers from 1-9
^ : start of string
$ : end of string
Demo
Comments
[1-9]|1[012] works for greedy quantifiers (that try to match as much as they can) but will not match 10 for lazy quantifiers because as soon as it sees 1 it will stop. Try this at https://regex101.com/
[2-9]|1[012] will work with lazy quantifiers
