I want to print all names with the example below. Names are random every time.
txt = "[something name=\"Paul\" other=\"1/1/1\"][something name=\"James\" other=\"4/3/5\"][something name=\"Victor\" other=\"7/2/6\"][something name=\"Jane\" other=\"4/3/6\"]" I know how to print first of this names:
print str(txt[txt.index('[something name=\"')+17:txt.index(' other')-1]) but how can I print all? I need to print all names in new line:
Paul James Victor Jane Looks like you can use regex here:
import re txt = "[something name=\"Paul\" other=\"1/1/1\"][something name=\"James\" other=\"4/3/5\"][something name=\"Victor\" other=\"7/2/6\"][something name=\"Jane\" other=\"4/3/6\"]" for name in re.findall('name\=\\"(.*?)\\\"', txt): print name Prints:
Paul James Victor Jane Another approach would be to split the string as follows:
txt = "[something name=\"Paul\" other=\"1/1/1\"][something name=\"James\" other=\"4/3/5\"][something name=\"Victor\" other=\"7/2/6\"][something name=\"Jane\" other=\"4/3/6\"]" for x in txt.split(']'): if len(x): print x.split('"', 2)[1] Giving:
Paul James Victor Jane 