Using #define for an if statement error

Question

I'm trying to create a readable function that will contain a large amount of repeating if statement using a section of my code below.

#define if_identifier(finder, to_find) if((finder = msg.find(to_find)) != std::string npos) std::string Utility::Decode(const char* buffer, int &playerID) { std::string msg(buffer); size_t identifier; if_identifier(identifier, "P_ID:[") { } }

Why does this code cause a type name is not allowed error?

Define a function instead of a macro, in the cases where you'd need that. But here, consider using a table of identifiers and a loop instead of multiple near-identical if statements. Think DRY: Don't Repeat Yourself. — Cheers and hth. - Alf
– Cheers and hth. - Alf, Commented Sep 25, 2015 at 2:56

MikeCAT · Accepted Answer · 2015-09-25 02:43:38Z

3

Because junk std::string is there.

Try changing std::string npos to std::string::npos.

answered Sep 25, 2015 at 2:43

MikeCAT

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